LIC AAO Final Result 2019 Declared! Check Scorecard & Merit List | Sarkari Result & Online Form

LIC Assistant Administrative Officer (AAO) Result 2019 — Overview

The Life Insurance Corporation of India (LIC) has announced the results for its 2019 recruitment drive for the post of Assistant Administrative Officer (AAO). The results have been released for all stages of the selection process, including the Preliminary and Mains examinations, as well as the final merit list. The Preliminary exam results were declared on June 05, 2019, followed by the Mains exam results on July 29, 2019. Candidates who participated in any stage of this competitive recruitment process can now view their qualification status on the official portal.

How to Check the LIC AAO 2019 Result

1. Visit the official website of the Life Insurance Corporation of India (LIC).
2. Navigate to the ‘Careers’ section, typically found at the bottom of the homepage.
3. Locate and click on the link for the “Recruitment of Assistant Administrative Officer 2019”.
4. Select the appropriate link for the result you wish to check (Preliminary, Mains, or Final Result).
5. A PDF file containing the list of qualified candidates will open. Use the search function (Ctrl+F) to find your roll number or name.

What Happens Next?

Candidates who feature in the final merit list are required to proceed with the subsequent stages of the selection process. This includes a mandatory pre-recruitment medical examination to ensure they meet the fitness standards for the role. Following a successful medical check-up, candidates must attend a document verification session. During this stage, all original documents related to educational qualifications, age, and category will be scrutinized. Only after the successful verification of all credentials will the final appointment letters be issued by the corporation.For the most accurate and direct information, candidates are strongly encouraged to check their results and any further announcements exclusively on the official LIC website.